Angle of Elevation of the Ground

[nycmathguy]

Section 6.1

Looking for set up only.

 

[MathLover1]

<B=42°
BC=17m
AC=10m

from right triangle, angle A=90° -42° =48°
let angle opposite to AC be x, than

sin(48)/17=sin(x)/10
sin(x)=(sin(48)/17)*10
sin(x)=0.4371440149867
x=sin^-1(0.4371440149867)
x=25.92°

then θ =42° -25.92°=16.08°

 

[nycmathguy]

<B=42°
BC=17m
AC=10m

from right triangle, angle A=90° -42° =48°
let angle opposite to AC be x, than

sin(48)/17=sin(x)/10
sin(x)=(sin(48)/17)*10
sin(x)=0.4371440149867
x=sin^-1(0.4371440149867)
x=25.92°

then θ =42° -25.92°=16.08°

I was looking for the set up only. I thank you for working out the problem. Moving forward do not work out applications unless otherwise indicated. The whole idea for my threads is to learn precalculus.