Another problem, alg, I think

Discussion in 'General Math' started by Bill, Feb 5, 2006.

  1. Bill

    Bill Guest

    Painter A paints a room in 6 hours; painter B paints a room in 7
    hours. How long does it take them to paint a room together?

    I appreciate all the help I am getting from you guys.

    bill
     
    Bill, Feb 5, 2006
    #1
    1. Advertisements


  2. Ok we know that A paints 1/6 of room in an houtr and painter B
    paints 1/7 of a room in an hour

    So when they are painting to gether they paint 1/6 + 1/7 of a room in
    an hour - that equals 13/42 of a room in an hour.

    so it would take both of them together 42/13 hours to paint the
    room


    Patrick
     
    Patrick FitzGerald, Feb 5, 2006
    #2
    1. Advertisements

  3. Painter A paints a room in 6 hours; painter B paints a room in 7
    Or, if you don't like fractions:

    In 42 hours, A paints 7 rooms and B paints 6, so they have painted 13
    between them, and so (warning, fraction ahead), they paint 1 room in
    42/13 hours.
     
    thargle_whoosh, Feb 5, 2006
    #3
  4. Bill

    Aggie1956 Guest

    In equation form:
    Painter A can do 1/6 of the room in one hour.
    Painter B can do 1/7 of the room in one hour.

    Let t = time (in hours) that they will work together to get one job (the
    room) done.

    (1/6)t + (1/7)t = 1
    7 t + 6 t = 42
    13 t = 42
    t = 42/13
     
    Aggie1956, Feb 5, 2006
    #4
    1. Advertisements

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.