See attachment. I say the area in terms of x and y is A = length • width or x•y. I know that y = sqrt{36 - x^2}. A(x) = x•y Replace y with sqrt{36 - x^2}. A(x) = x•sqrt{36 - x^2} Is this function? If not, why not? See attachment for domain. I say the domain is (-00, -6] U [6, 00). Yes? [ATTACH=full]57[/ATTACH] [ATTACH=full]58[/ATTACH]