MathLover1 Joined Jun 27, 2021 Messages 2,989 Reaction score 2,884 Oct 1, 2021 #2 the area of the rectangle is A=L*W from the graph we see that L=10 W=y coordinate of the (x,y) since y=sqrt(36-x^2), we have A=10*sqrt(36-x^2) domain: {x element R : -6<=x<=6}
the area of the rectangle is A=L*W from the graph we see that L=10 W=y coordinate of the (x,y) since y=sqrt(36-x^2), we have A=10*sqrt(36-x^2) domain: {x element R : -6<=x<=6}
nycmathguy Joined Jun 27, 2021 Messages 5,386 Reaction score 422 Oct 1, 2021 #3 MathLover1 said: the area of the rectangle is A=L*W from the graph we see that L=10 W=y coordinate of the (x,y) since y=sqrt(36-x^2), we have A=10*sqrt(36-x^2) domain: {x element R : -6<=x<=6} Click to expand... Since questions are easy enough to confuse.
MathLover1 said: the area of the rectangle is A=L*W from the graph we see that L=10 W=y coordinate of the (x,y) since y=sqrt(36-x^2), we have A=10*sqrt(36-x^2) domain: {x element R : -6<=x<=6} Click to expand... Since questions are easy enough to confuse.