Chapter 1 Calculus 1 [ATTACH=full]2346[/ATTACH] Question 27 Find (3 + h) f(3 + h) = 4 + 3(3 + h) - (3 + h)^2 f(3 + h) = 4 + 9 + 3h - (9 + 6h + h^2) f(3 + h) = 4 + 9 + 3h - 9 - 6h - h^2 f(3 + h) = 4 + 3h - 6h - h^2 Find f(3). f(3) = 4 + 3(3) - (3)^2 f(3) = 4 + 9 - 9 f(3) = 4 We now have: [4 + 3h - 6h - h^2 - 4]/h (3h - 6h - h^2)/h 3 - 6 - h Answer: -3 - h What does the answer mean?