# Difference Quotient...3

Discussion in 'Calculus' started by nycmathguy, Mar 27, 2022.

1. ### nycmathguy

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Chapter 1
Calculus 1

Question 27

Find (3 + h)

f(3 + h) = 4 + 3(3 + h) - (3 + h)^2

f(3 + h) = 4 + 9 + 3h - (9 + 6h + h^2)

f(3 + h) = 4 + 9 + 3h - 9 - 6h - h^2

f(3 + h) = 4 + 3h - 6h - h^2

Find f(3).

f(3) = 4 + 3(3) - (3)^2

f(3) = 4 + 9 - 9

f(3) = 4

We now have:

[4 + 3h - 6h - h^2 - 4]/h

(3h - 6h - h^2)/h

3 - 6 - h

nycmathguy, Mar 27, 2022
2. ### MathLover1

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correct

What does the answer mean? -> mean you have an expression in terms of h as an answer, and what will be the answer depends on value(s) of h

MathLover1, Mar 27, 2022
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3. ### nycmathguy

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Ok. So far so good in terms of calculus.

nycmathguy, Mar 27, 2022
4. ### HallsofIvy

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It means that the average rate of change in f(x) between x and x+h is -3- h. Notice that with regular algebra, the question "what does the instantaneous rate of change", the rate of change with no change at all in x, makes no sense- if x does not change f(x) does not change so there is no "rate of change". But wth the limit concept, we can define the "instantaneous rate of change" as the limit as h goes to 0 and lim -3- h= -3 so the instantaneous rate of change of f(x) at x is -3.

HallsofIvy, Mar 29, 2022
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