Distance From Boat to Shoreline

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jan 10, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.1

    Looking for the set up only.

    Screenshot_20220109-195849_Samsung Notes.jpg
     
    nycmathguy, Jan 10, 2022
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  2. nycmathguy

    MathLover1

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    Since the boat is traveling at a rate of 10 miles per hour (60 minutes), that same boat travels 2.5 miles in 15 minutes.

    Draw a diagram. [On the diagram shown, all angles are in degrees.] This diagram should show two triangles -- one with a 72° angle to the lighthouse, and another with a 66° angle to the lighthouse.

    [​IMG]


    Find the complementary angles of 18° and 24°.
    The angle immediately under the boat's present location measures 66°+90°=156°.
    For the angle with the smallest measure in the diagram, I have used the fact that
    6°=24°−18°, but you may also subtract the sum of 156° and 18° from 180°.

    This gives us an oblique triangle whose angles measure 156°,18°,and 6° and one of whose sides measures 2.5 miles.

    You may now use the Law of Sines to find the direct distance to the lighthouse.

    sin6°/2.5=sin18°/d

    This gives a direct distance of approximately 7.4 miles.
    If you want the perpendicular distance to the shore, you may now use basic trigonometry. If y is the perpendicular distance, then

    y/7.4=sin23°

    y=7.4/sin23°

    This is approximately 2.9 miles.
     
    MathLover1, Jan 10, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Very nice. Thank you.
     
    nycmathguy, Jan 11, 2022
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