Section 6.6 [ATTACH=full]2026[/ATTACH] [ATTACH=full]2027[/ATTACH] [ATTACH=full]2028[/ATTACH]

you have , that is incorrect need to do this way: = =...........rationalize = = = =0.086824+0.492405*i you did same mistake with do it like I did above and result should be: -0.735626 +1.01062*i

you cannot factor out 1/2 and write cos and sin as difference of angles from numerator and denominator that is WRONG compare to (cos(x)+sin(x))/(cos(y)+sin(y))-> you cannot write it as cos(x-y)+sin(x-y)

that is new to me, I do not recall that method but it's much shorter (I was always doing rationalization) I know the theorem for division of complex numbers is: Let \( z1=(r1,θ1)\) and \(z2=(r2,θ2)\) be complex numbers expressed in polar form, such that z2≠0. Then: \(z1/z2=r1/r2(cos(θ1-θ2)+i*sin(θ1-θ2))\) Proof \(z1/z2 =r1(cosθ1+isinθ1/r2(cosθ2+isinθ2)\).Definition of Polar Form of Complex Number =\((r1(cosθ1+isinθ1))(r2(cosθ2−isinθ2))(r2(cosθ2+isinθ2)(r2(cosθ2−isinθ2))\).multiplying numerator and denominator by \(r2(cosθ1-isinθ1) \) =\(r1r2(cos(θ1−θ2)+isin(θ1−θ2))/(r2^2(cos(θ2−θ2)+isin(θ2θ2))\).Product of Complex Numbers in Polar Form =\( (r1(cos(θ1−θ2)+isin(θ1−θ2)))/(r2(cos0+isin0))\) =\((r1/r2)(cos(θ1−θ2+isin(θ1-θ2)) \) ........Cosine of Zero is One and Sine of Zero is Zero

What do I do? Unfortunately, the answers to even number problems are not listed in the back of the book as you already know. In that case, why not do 41 and 43? I will then check the answer listed on the back of the book by Larson. Sounds good?

To divide $\frac{a+ bi}{c+ di}$, multiply both numerator and denominator by the conjugate of the denominator: