Domain, x-intercept & Vertical Asymptote of Logarithmic Functions...1

Discussion in 'Other Pre-University Math' started by nycmathguy, Oct 16, 2021.

  1. nycmathguy

    nycmathguy

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    Section 3.2
    42 & 44

    20211016_164253.jpg

    Find the domain, x-intercept and vertical asymptote of each logarithmic function. Graph each function.

    Note: Do 42 and 44 as a guide for me to do the rest.
     
    nycmathguy, Oct 16, 2021
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  2. nycmathguy

    MathLover1

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    42.
    [​IMG]

    Domain:
    The domain of a function is the set of input or argument values for which the function is real and defined
    since you have a logarithmic function, domain is

    x element of R: x>0

    Interval Notation:
    (0,infinity )

    Range:
    -infinity < f(x) <infinity
    Interval Notation:
    (-infinity ,infinity ight)


    x -intercept: [​IMG] => x=1

    (1,0)

    Asymptotes: Vertical, x=0, Horizontal: none
    upload_2021-10-16_19-18-1.png


    44. [​IMG]

    domain:
    x element of R: x>3
    Interval Notation:
    (3,infinity )

    Range:
    -infinity < h(x) <infinity
    Interval Notation:
    (-infinity ,infinity ight)

    x-intercept: [​IMG] only if x=4

    (4,0)

    Asymptotes: Vertical, x=3, Horizontal: none

    upload_2021-10-16_19-31-5.png
     
    MathLover1, Oct 17, 2021
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  3. nycmathguy

    nycmathguy

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    1. Explain how you found the x-intercept.

    2. Are you saying the domain is the argument of log function set to be > 0?

    3. How did you get the range?

    4. Graphing the function is the best way to determine the vertical asymptote. Yes?
     
    nycmathguy, Oct 17, 2021
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  4. nycmathguy

    MathLover1

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    1. to find x-intercept, set f(x) to zero

    log (6 ,x )=0.

    2.
    then write as exponential
    x=6^0=> x=1
    log(4,x-3)=0=>x-3=4^0 =>x-3=1 =>x=1+3=>x=4

    3.
    Whatever base we have for the logarithmic function, the range is always "All Real Numbers"
    upload_2021-10-16_20-9-45.jpeg


    4. yes
     
    MathLover1, Oct 17, 2021
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  5. nycmathguy

    nycmathguy

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    Great reply. I will try a few tomorrow and post here.
     
    nycmathguy, Oct 17, 2021
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