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David Cohen
View attachment 1867
AB=8 =>hypothenuse which is divided in two parts
let say h1 ( upper triangle ) and h2 (lower triangle )
so, h1=8-h2
and sin(theta)=4/h2
h2=4/sin(theta)
then h1= 8-4/sin(theta)
now we need cos to find x
cos(theta)=x/h1
cos(theta)=x/(8-4/sin(theta))
x=(8-4/sin(theta))cos(theta)
x=(8-4/sin(theta))cos(theta)
no I haven't see it before, but I see the picture you provided
sometimes pictures are worth more than thousand words![]()