David Cohen [ATTACH=full]1865[/ATTACH]
AB=8 =>hypothenuse which is divided in two parts let say h1 ( upper triangle ) and h2 (lower triangle ) so, h1=8-h2 and sin(theta)=4/h2 h2=4/sin(theta) then h1= 8-4/sin(theta) now we need cos to find x cos(theta)=x/h1 cos(theta)=x/(8-4/sin(theta)) x=(8-4/sin(theta))cos(theta) x=(8-4/sin(theta))cos(theta)
no I haven't see it before, but I see the picture you provided sometimes pictures are worth more than thousand words