Express x As Function of theta

Joined
Jun 27, 2021
Messages
5,386
Reaction score
422
David Cohen

IMG_20220130_130505.jpg
 
upload_2022-1-31_18-16-29.png


AB=8 =>hypothenuse which is divided in two parts

let say h1 ( upper triangle ) and h2 (lower triangle )

so, h1=8-h2

and sin(theta)=4/h2
h2=4/sin(theta)

then h1= 8-4/sin(theta)

now we need cos to find x

cos(theta)=x/h1

cos(theta)=x/(8-4/sin(theta))

x=(8-4/sin(theta))cos(theta)

x=(8-4/sin(theta))cos(theta)
 
View attachment 1867

AB=8 =>hypothenuse which is divided in two parts

let say h1 ( upper triangle ) and h2 (lower triangle )

so, h1=8-h2

and sin(theta)=4/h2
h2=4/sin(theta)

then h1= 8-4/sin(theta)

now we need cos to find x

cos(theta)=x/h1

cos(theta)=x/(8-4/sin(theta))

x=(8-4/sin(theta))cos(theta)

x=(8-4/sin(theta))cos(theta)

How do you know what to do? Have you seen this question before?
 
no I haven't see it before, but I see the picture you provided :-)
sometimes pictures are worth more than thousand words :-)
 

Members online

No members online now.

Forum statistics

Threads
2,521
Messages
9,844
Members
694
Latest member
FannyTurnb
Back
Top