Discussion in 'Undergraduate Math' started by johnreed, Dec 28, 2011.

  1. johnreed

    johnreed Guest

    -------When we use a balance scale to measure weight [mg] we are
    making use of the quantity [g] that with respect to the balance scale
    function, is a consequence of the balance scale's location in space.
    The quantity [g] at the balance scale location acts uniformly on each
    pan of the balance scale and on the observer, and persists as a
    uniform attraction on the contents of each pan to bring the
    comparative resistance quantity mass [m] to balance in the attraction
    field that acts uniformly on atoms. The uniform quantity [g] at
    location allows the observer to measure comparative magnitudes of non-
    uniform atomic matter in conserved quantitative uniform units that the
    observer feels as resistance and defines as mass [m]. The balance
    scale compares the resistance of two pans of matter.

    [mg]1 = [mg]2 on the balance scale where [g] divides out because it is
    a uniform external to the balance scale influence on each pan.

    The balance scale compares at any location [g] the resistance [m] of
    the non-uniform pans of atomic matter. The observer feels the product
    [mg] at location [g]. The observer views the conserved comparative
    resistance [m] at any location, as a partial causal factor of the
    variable location product, weight [mg], that the observer feels.
    This is a sound conclusion.

    The observer also concludes that the weight [mg] is equal and opposite
    to a force the observer applies and feels [F=mg]. This is not a sound
    conclusion. The quantity [mg] is a resistance that is equal to a force
    the observer applies [F=mg]. This is a sound conclusion.

    The math works either way.
    johnreed, Dec 28, 2011
    1. Advertisements

  2. johnreed

    Country Boy

    Dec 15, 2021
    Likes Received:
    I have no idea what your purpose was in posting this!
    Country Boy, Dec 26, 2021
    nycmathguy likes this.
    1. Advertisements

  3. johnreed


    Jun 27, 2021
    Likes Received:
    I concur.
    nycmathguy, Dec 27, 2021
    1. Advertisements

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.
Similar Threads
There are no similar threads yet.