Find Direction & Speed of Wind

[nycmathguy]

Section 6.3

How is this done?

 

[MathLover1]

let speed of wind be w

w^2=875^2+800^2-2(875)(800)*cos(8)

w^2=1405625 - 1400000 cos(8°)
w^2=19249.70376
w=sqrt(19249.70376)
w=138.7 km/h

find heading bearing using law of sin

sin(B)/800=sin(8°)/138.7
sin(B)=800sin(8°)/138.7
sin(B)=0.8027
B=sin^-1(0.8027)
B=53.39°
heading bearing is 53.39°-32° =21.4°

 

[nycmathguy]

View attachment 1862


let speed of wind be w

w^2=875^2+800^2-2(875)(800)*cos(8)

w^2=1405625 - 1400000 cos(8°)
w^2=19249.70376
w=sqrt(19249.70376)
w=138.7 km/h

find heading bearing using law of sin

sin(B)/800=sin(8°)/138.7
sin(B)=800sin(8°)/138.7
sin(B)=0.8027
B=sin^-1(0.8027)
B=53.39°
heading bearing is 53.39°-32° =21.4°

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