# Find Equation of Tangent Line...2

Discussion in 'Calculus' started by nycmathguy, Jun 17, 2022.

1. ### nycmathguy

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Calculus
Section 3.1

Can you do 44 as a guide for me to do 43?
Show steps along the way.

Thank you.

nycmathguy, Jun 17, 2022
2. ### MathLover1

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44.

y=x-sqrt(x) at point (1,0)

first find the slope of tangent line

(dy/dx)(x-sqrt(x) )=1-1/(2sqrt(x))

compute the slope at point (1,0)

m=1-1/(2sqrt(1))=1-1/2=1/2

so far, tangent line is: y=(1/2)x +b

use point to calculate b:

0=(1/2)1+b

0=1/2+b

b=-1/2

tangent line is: y=(1/2)x-1/2

MathLover1, Jun 17, 2022
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3. ### nycmathguy

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Another easy step by step reply makes this a walk in the park.

nycmathguy, Jun 18, 2022
4. ### nycmathguy

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nycmathguy, Jun 18, 2022
5. ### MathLover1

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correct

MathLover1, Jun 18, 2022
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