Find Equation of Tangent Line...2

Discussion in 'Calculus' started by nycmathguy, Jun 17, 2022.

  1. nycmathguy

    nycmathguy

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    Calculus
    Section 3.1

    Can you do 44 as a guide for me to do 43?
    Show steps along the way.

    Thank you.

    Screenshot_20220617-122332_Samsung Notes.jpg
     
    nycmathguy, Jun 17, 2022
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  2. nycmathguy

    MathLover1

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    44.

    y=x-sqrt(x) at point (1,0)

    first find the slope of tangent line

    (dy/dx)(x-sqrt(x) )=1-1/(2sqrt(x))

    compute the slope at point (1,0)

    m=1-1/(2sqrt(1))=1-1/2=1/2

    so far, tangent line is: y=(1/2)x +b

    use point to calculate b:

    0=(1/2)1+b

    0=1/2+b

    b=-1/2


    tangent line is: y=(1/2)x-1/2

    upload_2022-6-17_15-3-58.png

     
    MathLover1, Jun 17, 2022
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  3. nycmathguy

    nycmathguy

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    Another easy step by step reply makes this a walk in the park.
     
    nycmathguy, Jun 18, 2022
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  4. nycmathguy

    nycmathguy

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    IMG_20220618_173853.jpg
     
    nycmathguy, Jun 18, 2022
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  5. nycmathguy

    MathLover1

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    correct

    upload_2022-6-18_16-46-8.png
     
    MathLover1, Jun 18, 2022
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  6. nycmathguy

    nycmathguy

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    Nice way to end of Saturday. The weekend is an illusion. I cannot believe Sunday is just a few hours away. Crazy!!!
     
    nycmathguy, Jun 18, 2022
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