Find Original Fraction

Discussion in 'Algebra' started by nycmathguy, Dec 2, 2021.

  1. nycmathguy

    nycmathguy

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    Screenshot_20211201-032329_Facebook.jpg

    Tell me if the set up is right.

    Numerator of original fraction = x - 8.
    Denominator of original fraction = x.

    Original Fraction = (x - 8)/x.

    Numerator of new fraction = (x - 8) + 1 = (x - 7).
    Denominator of new fraction = (x - 3).

    Here is my set up:

    (x - 7)/(x - 3) = 2/3

    Yes?
     
    nycmathguy, Dec 2, 2021
    #1
  2. nycmathguy

    MathLover1

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    correct
     
    MathLover1, Dec 2, 2021
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  3. nycmathguy

    nycmathguy

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    At least I can do the easy stuff. Some people can't even do that right.
     
    nycmathguy, Dec 2, 2021
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  4. nycmathguy

    MathLover1

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    (x - 7)/(x - 3) = 2/3

    x=15
    =>Original Fraction = (x - 8)/x=(15-8)/15=7/15

    check:

    (7+1)/(15-3)= 2/3
     
    MathLover1, Dec 2, 2021
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  5. nycmathguy

    nycmathguy

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    I got it right.
     
    nycmathguy, Dec 2, 2021
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  6. nycmathguy

    Country Boy

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    IF you first state that you are letting the denominator be "x" then you can say that the numerator is x- 8.
     
    Country Boy, Dec 29, 2021
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  7. nycmathguy

    nycmathguy

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    Ok. Noted.
     
    nycmathguy, Dec 30, 2021
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