Two positive numbers are in the ratio 3:4. The sum of thrice the first number and twice the second is 68. Find the smaller number. Let me see. 3(3x) + 2(4x) = 68 9x + 8x = 68 17x = 68 x = 68/17 x = 4 3x = 3(4) = 12 4x = 4(4) = 16 The smaller number is 12.