Finding the roots of a 6-degree polynomial

Discussion in 'Other Advanced Math' started by ZeroKool007, Dec 27, 2018.

  1. ZeroKool007

    ZeroKool007

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    Hello,
    I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

    equation.png

    Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0.

    Example: mx=6.3, Qx=0.4 ... this would give the results of
    A = 0.4890380
    B = 0.788825-0.86129i
    C = 0.788825+0.86129i

    Thanks,
    ZeroKool
     
    Last edited: Dec 27, 2018
    ZeroKool007, Dec 27, 2018
    #1
  2. ZeroKool007

    Country Boy

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    There is no general method of solving a sixth degree polynomial equation. In fact, it was proved, over 100 years ago, that for n> 4 there exist polynomial equations with solutions that can not be written as roots so no formula, similar to the quadratic and cubic formulas can exist for n> 4.
     
    Country Boy, Jan 4, 2022
    #2
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