How to find an area irregular quadrilateral

Joined
Aug 3, 2022
Messages
2
Reaction score
0
Hi,

Could anybody give a solution in finding the area of an irregular quadrilateral.
20220803_173800.jpg
 
divide irregular quadrilateral into rectangle and right triangle, find areas and add them up

rectangle have the length of 857 and the width of 43
so the area of the rectangle=857*43=36851

one leg of the right triangle (altitude) are 865-43=822 and the other leg is 857
the area of the right triangle= (1/2)822 *857=352227

the area of the irregular quadrilateral=36851+352227=389078
 
divide irregular quadrilateral into rectangle and right triangle, find areas and add them up

rectangle have the length of 857 and the width of 43
so the area of the rectangle=857*43=36851

one leg of the right triangle (altitude) are 865-43=822 and the other leg is 857
the area of the right triangle= (1/2)822 *857=352227

the area of the irregular quadrilateral=36851+352227=389078

Interesting. Nice reply.
 
To split the irregular quadrilateral into a rectangle and a right triangle, you first find the dimensions of each shape.

The rectangle has a length of 857 and a width of 43, so its area is 857 * 43 = 36,851 square units.

For the right triangle, one leg (altitude) is 865 - 43 = 822, and the other leg is 857. Applying the formula for the area of a triangle = (1/2)*base*height

the area of triangle = (1/2)*822*857 = 352,227 square units.

Adding the areas of the rectangle and the right triangle together, the total area of the irregular quadrilateral is 36,851+352,227=389,078 square units.

It is quite difficult to solve such type of problem. Especially you need expert help, whenever you experience such type of problem in your assignment. I would suggest you to visit MathsHomewporkHelp.com for your assignment solution. You can also contact them at +1 (315) 557-6473.
 

Members online

No members online now.

Forum statistics

Threads
2,530
Messages
9,859
Members
697
Latest member
lemon in icewine
Back
Top