irrational and real exponents

Discussion in 'Mathematica' started by congruentialuminaire, Mar 30, 2009.

  1. Hello MathGroup:

    Originally I was confused also about imaginary exponents also but help
    cleared that up.

    Help for Power also has this sentence: "For certain special arguments,
    Power automatically evaluates to exact values."

    Does this imply that for irrational and real exponents, they are
    "truncated" to rationals before they are evaluated?

    Thanks in advance for any info on this.

    Roger Williams
    Franklin Laboratory
     
    congruentialuminaire, Mar 30, 2009
    #1
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  2. Hi,

    Mathematica will never truncate anything. This mean
    I^2 is evaluated to -1 and E^(-2 Pi I) is evaluated to 1

    Regards
    Jens
     
    Jens-Peer Kuska, Mar 30, 2009
    #2
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  3. congruentialuminaire

    dh Guest

    Hi Roger,

    No, I would rather think at cases like e.g.: E^(Pi I), 0.1^0, 0.1^Infinity

    Daniel





     
    dh, Mar 31, 2009
    #3
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