[ATTACH=full]998[/ATTACH]

1/log(2,pi)+log(5,pi)>2 use the rule: log(b,x) = log(k,x)/log(k,b) log(2,pi)= log(pi,pi)/log(pi,2)............log(pi,pi)=1 log(2,pi)= 1/log(pi,2). log(5,pi)= 1/log(pi,5) 1/( 1/log(pi,2))+(1/log(pi,5))>2 log(pi,2)+log(pi,5))>2 log(pi,2*5)>2 log(pi,10)>2->true

Nice job like always. It is easier, however, to read your answers on paper just like I post my threads.