# Maths + Fibonacci.LEAP YEAR.

Discussion in 'General Math' started by Don McDonald, Feb 5, 2004.

1. ### Don McDonaldGuest

Maths + Fibonacci.LEAP YEAR.
Nz.general

05.02.04 02:08 SENT.
..Pgms.Prime.60minutes
..Pgms.Prime.Creat5555
..Pgms.Prime.CBS60mn04 > this file.

my family ( for argument's sake) is 5ft 2in tall x 25 inch waist.
How many sq metres does it multiply out to? The figures are exact.
Intriguing!

Enter Google: 62 in * 25 in in square meters =.

occurs in 29.2.1904 and then every fourth year
until 29.2.2096 inclusive.

One common year is 365 days.
Four years is 1461 days. 100 years is 36524 days.
And 400 years is 146097 days = 20871 weeks. (The Gregorian
calendar.)

Eight leap days every 33 years, (equals 2424 /9999, )
is a more accurate astronomical figure, 8/33 = .2424... days.
Compare Tropical year = 365.242199 mean solar days.

However, this is not a whole number of 7 day weeks.

My pandigital cryptarithm,

"YEAR = MONTHS = 365" has solution.
(3^6+1)/2 =5(70+9^(4/8)).
or 36+1/2.

I walked 1 km from my home and spotted car registrations
that expire on 29.2.2004 (Leap day.)

SF 4159, UR 9876, MB 8752, NH 620, LOWDWN,
UW 8634. I wonder why? How old are my neighbours' cars?

Donald S. McDonald. extra below..+++

I saw the Fibonacci sequence, number plate "11235?" at C Place,
Wgtn.
should calculate 1123,8513.

Of course, the first 7 Fibonacci numbers,
-which are the sequence of sums of the
2 immediately preceeding terms, beginning (0, 1); continue 1 2 3 5 8
13 and 21.

It is quite unexpected that they all turned
up in tonight's NZ Keno 20/80 draw #2555, Wed 04 Feb. 2004.
(1 chance in 41 thousand.)

But tonight's draw #2555 also included <at least>
11 prime numbers lucky numbers in Keno 20/80, -
numbers greater than 1 divisible only by itself and
unity, 2 3 5 7 13 17 31 41 47 61 67.
(1 chance in 397.)

==
The birthday problem. (Don.)

There are 366 different days of the year.
However, take just 23 people and there
should be greater than 50 per cent chance
that 2 of them may share a birthday.

[calculation ** Casio FX-82 schools sci-calc.
1-366 nPr 23/ 366^ 23= .5063. **]

There are 3838,380 different lotto combinations, 40-choose-6.
Don showed 2 winning combinations of 1st division that
differed just by 2 in the lowest number.

You have heard about the Birthday problem(): if there are
23 people in a room then the probability is greater than 50 %
that at least 2 of them will share a birthdate. /month/

So, you should be able to solve this one:
I have found ****5 repeats, almost 6 repeats***
between NZ Lottos draws #172 #542.

There have been 584 draws of New Zealand Lotto 6/40 to date, 28.09.98.
Six (6) lucky nos. from 1-40 are drawn from the hopper (barrel)
without replacement. What are the odds that out of all
the 584 draws, at least 2 draws had the exact same combination?

==

Suppose there are 100 billion different possible fingerprints?
What then is the chance that, among 1 bn fingerprints,
2 individuals are not distinguished? (Calculus.) The argument in
60 Minutes programme showed that, in real life, fingerprints
are 'matched' manually.

If two galaxies of stars collide, // I was able to reckon the chance of
2 stars hitting head-on. One from each galaxy.

A few mathematical sequences have turned up.

Seven out of 7 'powers of 2' = 1 2 4 8 16 32 64.
(chance 1 in 40,979 = 80 nCr 7 / 20 nCr 7.)
****** > keno249pw2 //keno2048.

/32, 1, 64, 8, 16, 4, 2, count [7]
7 x powers of '2'. New Zealand Keno draw #249, 13 Oct. 1995.

6;50 24.04.01
ANZAC odd multiples of 7. [it won bigtime several times before!
25.4.1997, 25.4.2000, odds 6.6 million, 1 day apart.]
formula {10n, 14n+7} pix 12 correct out of 14.
#645? On ANZAC Day.
[australia new zealand army corps. Gallipoli?]

don.mcdonald.
new zealand.

Don McDonald, Feb 5, 2004