One Dice

Jack tosses one die. What is the probability of the die landing on 5?

Let me see.

There are 6 numbers on a die: 1, 2, 3, 4, 5, 6.
There is only one number 5 on that list.

Let E = landing on 5

So. P(E) = 1/(total numbers listed).

P(E) = 1/6

Yes?

 

Yes

 

This is an easy question. Look for more precalculus questions during the week. I will also post probability questions.

 

When I saw the title "One Dice" I was ready to open this thread and scream and shout! But then I saw that in the body you write "die". Well done!

 

I didn't see "die"

 

"Jack tosses one die. What is the probability of the die landing on 5?
Let me see.
There are 6 numbers on a die: 1, 2, 3, 4, 5, 6."
Credit where credit is due.

 

Seriously?

 

Seriously, I didn't.

 

I don't like the word DIE.

 

I don't like the word "fudge"- but I eat it anyway.

 

Dice works for me.