Planet Mars

[nycmathguy]

Exercises 1.4

For part (a), I must evaluate each interval [a, b] this way:

Let A(t) = average velocity

A(t) = [(10(b) - 1.86(b)^2] - [(10(a) - 1.86(a)^2] ÷ (b - a)

For part (b), I must find derivative of the given function and then evaluate when t = 1.

Yes

 

[MathLover1]

use

b. yes
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t.

 

[nycmathguy]

use
View attachment 620

b. yes
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t.

I will take mt time through the calculus textbook. I will do question 6 parts a and b and show my work here tomorrow.

 

[nycmathguy]

use
View attachment 620

b. yes
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t.

Part (a)

Part (b)

 

[MathLover1]

correct

 

[nycmathguy]

correct

Thank you.

 

[HallsofIvy]

Exercises 1.4

View attachment 614

For part (a), I must evaluate each interval [a, b] this way:

Let A(t) = average velocity

A(t) = [(10(b) - 1.86(b)^2] - [(10(a) - 1.86(a)^2] ÷ (b - a)

For part (b), I must find derivative of the given function and then evaluate when t = 1.

Yes

Yes, that is what you are to do. Why haven't you done it?

 

[nycmathguy]

Yes, that is what you are to do. Why haven't you done it?

I posted this and other calculus 1 questions when I thought it was a good idea to study this course and precalculus at the same time. Bad idea.