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Section 6.6
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Apply Perfect Cube Formula: (a-b )^3=a^3-3a^2b+3ab^2-b^3 for thewhere \(a=1\) and \(b=sqrt(3)*i\)![]()
=\(4(1^3-3*1^2*sqrt(3)*i+3*1(sqrt(3)*i)^2-(sqrt(3)*i)^3\)........simplify
=\(4(-8)\)
=\(-32\)