Power of a Complex Number...3

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Feb 27, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.6

    Screenshot_20220225-174727_Samsung Notes.jpg

    IMG_20220226_190113.jpg

    IMG_20220226_190120.jpg

    IMG_20220226_190132.jpg
     
    nycmathguy, Feb 27, 2022
    #1
  2. nycmathguy

    MathLover1

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    [​IMG]

    Apply Perfect Cube Formula: (a-b )^3=a^3-3a^2b+3ab^2-b^3 for the [​IMG] where \(a=1\) and \(b=sqrt(3)*i\)

    =\(4(1^3-3*1^2*sqrt(3)*i+3*1(sqrt(3)*i)^2-(sqrt(3)*i)^3\)........simplify

    =\(4(-8)\)

    =\(-32\)
     
    MathLover1, Feb 27, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    I can't get one single question right. Sad.
     
    nycmathguy, Feb 27, 2022
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