probability of a doz. Left-foot jandals tossed up by cyclone. (teara, Stats, Coriolis.)

Discussion in 'General Math' started by don.lotto, Jun 13, 2006.

  1. don.lotto

    don.lotto Guest

    probability of a doz. Left-foot jandals tossed up by
    cyclone. (teara, Stats, Coriolis.)

    "A scientific survey of (New Zealand) beach
    litter between 1974 and 1997 seems to offer
    'categorical proof' of the left-footed flotsam jandal
    phenomenon." (?)

    Err, they must be joking!"Of the 21 jandals and shoes stumbled upon by
    scientist Bruce Hayward, 70 per cent - nearly 15
    footwear items - were found to be left-footed..."This is from .. click link...

    http://www.google.co.nz/search?hl=en&q=left+foot+jandals+culture+nz&btnG=Search&meta=

    a DominionPost, wellington, New Zealand piece by Lane
    Nichols, 12.06.2006
    www.stuff.co.nz

    Indeed, project manager Jock Phillips, for NZ culture
    and history online encyclopedia, said on Radio New
    Zealand that "the figure is accurate."
    Are you sure? CAN it be 70 per cent AND... NEARLY 15
    out of 21.

    link www.radionz.co.nz ?? audio.

    Try 14 out of 21 = 2/3 ~ 67%, less than 70 %.
    Try 15 out of 21 = 5/7 ~ 71.4%, more than 70%.

    For a long shot, how about 14.7 / 21 = 7/10 = 70%
    BINGO!
    That's counting a 0.7 bit of jandal, though!

    A mathematician (called my brother) replied to me that
    a 70 : 30 percent proportional split of 21 Left/Right
    footwear items is statistically 'so little unusual'
    that it should never have been reported in an online
    encyclopedia,.... teara.

    Binomial discrete probability distribution, 95%
    C.I.... confidence interval
    = np +/- Z*sqrt(npq.)

    I suspect anyone who does it that way will be as
    'unreliable as margin of error.'

    Pushing it further, look at 'odd versus even keno
    numbers' for a remarkable contrast; instead of
    left-foot vs. right-foot jandals.!

    I found one-quarter of possible lucky nos picked 65%
    of the numbers drawn, #3120. AT LEAST 13 out of 20
    lucky numbers had [formula] 'an odd number of 10s and
    odd units, e.g. 10s 30s 50s 70s.' Above.

    I produced a trusty wall-chart for all such
    probabilities. This one has odds of 1 in 110 thousand
    and was supposed random.
    (I am quite high, the 8th best mathcn I know in
    Newtown.. RW WT LC JF MD DW RY.-- and I can say what I
    like.)

    DID X = {1 2 3 4 5 6} come up in the lottery?

    A small DEC-SEPT-ION !!!, 10X +7 = 17,27,37,47,57,56.
    Just 24 hrs ago, opening of teara, 12.6.06 #4168.

    YES!! Pix 6/6 correct, Odds 1 : 7753 from memory.

    Keno results have a hypergeometric distribution,
    meaning numbers are 'drawn WITHOUT REPLACEMENT.'
    This is far harder to sustain a bias.

    In simple language, if there had been 7 odds out of
    the first 10 nos. out of the barrel, then odd numbers
    are depleted, fewer odds remain. So, perhaps fewer
    odds should be expected to be drawn in the second 10
    nos. drawn.

    odd tens and odd units.= 80*.5*.5 possible. ==20.

    expected 20*20/80 = 5. Actual = 13. very rare.
    Donald S. McDonald.
     
    don.lotto, Jun 13, 2006
    #1
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