Raffle roll

Discussion in 'Undergraduate Math' started by Dusktreader, Jan 11, 2005.

  1. Dusktreader

    Dusktreader Guest

    Suppose you have a roll of raffle tickets who's outer radius is R and
    the inner radius (the dowel) is r. Given the length of a ticket, l,
    and it's width w, what is the formula that could be used to calculate
    the number of tickets in the roll?

    I'm drawing a blank on this one. I can't seem to think of an integral
    that would work for this problem.
     
    Dusktreader, Jan 11, 2005
    #1
    1. Advertisements

  2. Dusktreader

    Mike Terry Guest

    By w you mean the thickness of a ticket I guess? Rather than looking at
    integrals, you can look at areas when viewed from the end, i.e. looking
    along the direction of the dowel. You know the area between the outer and
    inner radii, and the area of a single ticket...

    Regards,
    Mike.
     
    Mike Terry, Jan 11, 2005
    #2
    1. Advertisements

  3. Dusktreader

    Dusktreader Guest

    That seems like a good approach. However, it would seem that finding
    the total volume of the raffle roll and dividing it by the volume of a
    single ticket would be the way to go with that.
     
    Dusktreader, Jan 11, 2005
    #3
  4. Dusktreader

    Mike Terry Guest

    Well finding either an accurate volume or an accurate thickness for a ticket
    would not be easy to do directly - I can only think that you would produce a
    roll with a known number of tickets, and calculate the volume of the roll,
    then divide by number of tickets. Having done this once, however, you could
    use the result for calculating the number of tickets in different size
    rolls...
     
    Mike Terry, Jan 11, 2005
    #4
    1. Advertisements

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.