resizing rows into colum

Hello,

I have a matrix with 2 rows and 500 columns. I need to reshape it to be 200 rows and 5 columns, with the original matrix chopped off after the 5 column for each row and the remaining moving to the next row.

for example what I have now is

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32

i want it to look like
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
26 27 28 29 30
31 32..and so on

 

X=reshape(X',[5 200])';

 

Hi Alan,

thanks for the response..actually I made a mistake in my example...the way it is set up now it is

1 2 3 4 5 11 12 13 14 15
6 7 8 9 10 16 17 18 19 20
21 22 23 24 25 31 32
26 27 28 29 30

you see the pattern...?

So I want it to look like this...

1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
26 27 28 29 30
31 32..and so on

any ideas?

Thanks!

 

Not the most elegant, but...
A = [1 2 3 4 5 11 12 13 14 15;
6 7 8 9 10 16 17 18 19 20;
21 22 23 24 25 31 32 33 34 35;
26 27 28 29 30 36 37 38 39 40];
B = [];
for i =1:numel(A)/length(A)/2
B = [B;A(i*2-1,1:5);A(i*2,1:5);A(i*2-1,6:10);A(i*2,6:10)];
end

 

You can do it without for loops:
A=[1:5 11:15; 6:10 16:20; 21:25 31:35; 26:30 36:40; 41:45 51:55; 46:50 56:60]
tic
n=numel(A);
B=reshape(A,[n/10,5,2]);
C=permute(B,[2 1 3]);
D=reshape(C,[10 n/20 2]);
E=permute(D,[3 2 1]);
F=reshape(E,[n/10 10])';
G=reshape(F,[5 n/5])'
toc

but the for loop solution is much faster. Maybe its worth it if you can condense some of those reshape and permute calls, otherwise just use the for loop.

 

What about:

A=[1:5 11:15; 6:10 16:20; 21:25 31:35; 26:30 36:40; 41:45 51:55; 46:50 56:60] ;
B = mat2cell(A,[2 2 2],[5 5]).'
B = cat(1,B{:})

hth
Jos