right triangle

Discussion in 'General Math' started by C.A.Hall's Tax Service, Dec 2, 2004.

  1. ABC is a right-angled triangle with angle ABC = 90°.
    D is a point on AB such that CD bisects the angle ACB.
    E is a point on BC such that AE bisects the angle CAB.
    If AE = 9 cm and CD = 82 cm, find the length of AC.
     
    C.A.Hall's Tax Service, Dec 2, 2004
    #1
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  2. C.A.Hall's Tax Service

    Lynn Kurtz Guest

    Look at the following reference for relations about angle bisectors:

    http://mathworld.wolfram.com/AngleBisector.html

    Using those equations for your known lengths and the fact your
    triangle is a right triangle, I get negative answers using Maple.

    --Lynn
     
    Lynn Kurtz, Dec 2, 2004
    #2
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  3. C.A.Hall's Tax Service

    George Cox Guest

    Are you sure? Maybe CD = 8.2 cm?
     
    George Cox, Dec 3, 2004
    #3
  4. | ABC is a right-angled triangle with angle ABC = 90.
    | D is a point on AB such that CD bisects the angle ACB.
    | E is a point on BC such that AE bisects the angle CAB.
    | If AE = 9 cm and CD = 82 cm, find the length of AC.
    |
    |

    BC = 7.08
    AB = 8.27
    Therefore AC = 10.89
     
    mechy engineery, Dec 4, 2004
    #4
  5. |
    | || ABC is a right-angled triangle with angle ABC = 90.
    || D is a point on AB such that CD bisects the angle ACB.
    || E is a point on BC such that AE bisects the angle CAB.
    || If AE = 9 cm and CD = 82 cm, find the length of AC.
    ||
    ||
    |
    | BC = 7.08
    | AB = 8.27
    | Therefore AC = 10.89
    |

    Sorry wrong calc.

    Please ignore I rushed too much.
     
    mechy engineery, Dec 5, 2004
    #5
  6. C.A.Hall's Tax Service

    David Snook Guest

    | ABC is a right-angled triangle with angle ABC = 90°.
    | D is a point on AB such that CD bisects the angle ACB.
    | E is a point on BC such that AE bisects the angle CAB.
    | If AE = 9 cm and CD = 82 cm, find the length of AC.
    |
    |

    AC = ~82.2 CM

    AB = ~81.933 CM
    BC = ~6.615 CM

    Regards, David
     
    David Snook, Dec 5, 2004
    #6
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