Simple Harmonic Motion...2

write an equation for Simple Harmonic Motion if given:

given:
A = 4in,
f =1.5(rad/s)
max at t=0 => so, we have cosine function:

x ( t ) = A cos ( ω t + ϕ )

where A is the amplitude measured in meters or inches, t is the time measured in seconds, ω is the angular frequency with units of inverse seconds, ϕ is the phase shift measured in radian

since f= ω / 2π , then

1.5/s = ω / 2π
(1.5*2π) /s = ω
ω = (3π)(rad/s)

ϕ =0..... (because maximum is at t=0)

x ( t ) = 4cos ( 3π*t + 0 )
x ( t ) = 4cos ( 3π*t )

2. leaving to you to tray

 

Yes, I will do 2 when time allows this weekend. As you know, I am moving soon. I am dealing with packing, need to start searching for a new place to live, several doctor appointments in the next couple of weeks, etc.