Solve for X

Discussion in 'Algebra' started by Zartan, Sep 29, 2013.

  1. Zartan

    Zartan

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    Good day! Hoping someone can help me. I am fractionally impaired!

    m-x = 6n(m+1)
    ------
    x

    I think after I expand the right side I need to get rid of the fraction on the right by multiplying both sides by X. Is that even correct? And if it is how do I get rid of the X's on the right once I have them there?
     
    Zartan, Sep 29, 2013
    #1
  2. Zartan

    kmcandy14

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    I would first multiply the x on the denominator on the left by both sides like so:

    x*(m-x) = (6n(m+1))*x
    ------
    x

    This will cancel out the xes and create this:

    m-x= (6n(m+1))*x

    Which means yes, that you were correct...

    I think that you could make things a little easier by subtracting m from both sides:

    m-x=(6n(m+1))*x
    -m -m
    ------------------

    leaving you with this:

    -x=(6n(m+1))*x-m

    Then, I think that you would then distribute the 6n to te (m+1), leaving you with this:

    -x=(6nm+6n)*x-m

    or something like that. Let me get back to you about it (if you even still need it).

    Hope this helps! Sorry this was so late!
     
    kmcandy14, Apr 11, 2016
    #2
  3. Zartan

    kmcandy14

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    Yeah, I think I did something wrong. Again, let me get back to on that!
     
    kmcandy14, Apr 19, 2016
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  4. Zartan

    kmcandy14

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    I think next you might divide both sides by the x on the left and get -1= (6nm+6n) -m, but I think tat that confirms that I did something wrong...
     
    kmcandy14, May 7, 2016
    #4
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