Good day! Hoping someone can help me. I am fractionally impaired! m-x = 6n(m+1) ------ x I think after I expand the right side I need to get rid of the fraction on the right by multiplying both sides by X. Is that even correct? And if it is how do I get rid of the X's on the right once I have them there?
I would first multiply the x on the denominator on the left by both sides like so: x*(m-x) = (6n(m+1))*x ------ x This will cancel out the xes and create this: m-x= (6n(m+1))*x Which means yes, that you were correct... I think that you could make things a little easier by subtracting m from both sides: m-x=(6n(m+1))*x -m -m ------------------ leaving you with this: -x=(6n(m+1))*x-m Then, I think that you would then distribute the 6n to te (m+1), leaving you with this: -x=(6nm+6n)*x-m or something like that. Let me get back to you about it (if you even still need it). Hope this helps! Sorry this was so late!
I think next you might divide both sides by the x on the left and get -1= (6nm+6n) -m, but I think tat that confirms that I did something wrong...