# Solve for X

Discussion in 'Algebra' started by Zartan, Sep 29, 2013.

1. ### Zartan

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Good day! Hoping someone can help me. I am fractionally impaired!

m-x = 6n(m+1)
------
x

I think after I expand the right side I need to get rid of the fraction on the right by multiplying both sides by X. Is that even correct? And if it is how do I get rid of the X's on the right once I have them there?

Zartan, Sep 29, 2013
2. ### kmcandy14

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I would first multiply the x on the denominator on the left by both sides like so:

x*(m-x) = (6n(m+1))*x
------
x

This will cancel out the xes and create this:

m-x= (6n(m+1))*x

Which means yes, that you were correct...

I think that you could make things a little easier by subtracting m from both sides:

m-x=(6n(m+1))*x
-m -m
------------------

leaving you with this:

-x=(6n(m+1))*x-m

Then, I think that you would then distribute the 6n to te (m+1), leaving you with this:

-x=(6nm+6n)*x-m

or something like that. Let me get back to you about it (if you even still need it).

Hope this helps! Sorry this was so late!

kmcandy14, Apr 11, 2016
3. ### kmcandy14

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Yeah, I think I did something wrong. Again, let me get back to on that!

kmcandy14, Apr 19, 2016

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