Solve for x

[nycmathguy]

 

[MathLover1]

ln(2x+3)=5.8 .........by definition of log 5.8=ln(e^5.8)

ln(2x+3)=ln(e^5.8) if log same we have

2x+3=e^5.8

2x=e^5.8-3

x=(e^5.8-3)/2

x≈163.65

 

[nycmathguy]

ln(2x+3)=5.8 .........by definition of log 5.8=ln(e^5.8)

ln(2x+3)=ln(e^5.8) if log same we have

2x+3=e^5.8

2x=e^5.8-3

x=(e^5.8-3)/2

x≈163.65

I see that no matter how long ago we visited precalculus the information is firmly planted in your mind. This has never been me.