The Sine Law question

Discussion in 'Geometry and Trigonometry' started by DropDeadFred, Nov 4, 2017.

  1. DropDeadFred

    DropDeadFred

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    So I'm working my way through a grade ten academic math course and I make it to the sine law section. Then I come across this equation in one of the examples and I honestly don't understand what was done to line one to result in line two. The problem is solving for e using the sine law, basically a/sinA = b/sinB = c/sinC. In the example this line is stated:

    54.0/sin44 = e/sin50

    Then the following line states:

    e = 54.0 sin50/sin44

    I don't understand what was done in line one to get to line two. To me, to isolate "e" you would multiply both sides by "sin50" and result in:

    e = 54.0/sin44 X sin50

    Please explain to me how this workso_O
     
    DropDeadFred, Nov 4, 2017
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  2. DropDeadFred

    MathLover1

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    54.0/sin44 = e/sin50............cross multiply

    54.0*sin50 = e*sin44........both sides divide by sin44
    54.0*sin50/ sin44 = e*sin44/ sin44
    54.0*sin50/ sin44 = e*1
    54.0*sin50/ sin44= e
     
    MathLover1, Jul 7, 2021
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  3. DropDeadFred

    nycmathguy

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    Great job as always.
     
    nycmathguy, Jul 8, 2021
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  4. DropDeadFred

    MathLover1

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    ty, I didn't know it was your post
     
    MathLover1, Jul 8, 2021
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  5. DropDeadFred

    nycmathguy

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    It's not my post. I decided to thank you because DropDeadFred may not say thanks, which is very common here.
     
    nycmathguy, Jul 8, 2021
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  6. DropDeadFred

    MathLover1

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    you know that person?
     
    MathLover1, Jul 8, 2021
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  7. DropDeadFred

    nycmathguy

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    No. I don't know that person but this is a common thing on this site. Haven't you noticed that most people don't say thank you or at least acknowledge the tutor?
     
    nycmathguy, Jul 8, 2021
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