The Sine Law question

So I'm working my way through a grade ten academic math course and I make it to the sine law section. Then I come across this equation in one of the examples and I honestly don't understand what was done to line one to result in line two. The problem is solving for e using the sine law, basically a/sinA = b/sinB = c/sinC. In the example this line is stated:

54.0/sin44 = e/sin50

Then the following line states:

e = 54.0 sin50/sin44

I don't understand what was done in line one to get to line two. To me, to isolate "e" you would multiply both sides by "sin50" and result in:

e = 54.0/sin44 X sin50

Please explain to me how this works

 

54.0/sin44 = e/sin50............cross multiply

54.0*sin50 = e*sin44........both sides divide by sin44
54.0*sin50/ sin44 = e*sin44/ sin44
54.0*sin50/ sin44 = e*1
54.0*sin50/ sin44= e

 

Great job as always.

 

ty, I didn't know it was your post

 

It's not my post. I decided to thank you because DropDeadFred may not say thanks, which is very common here.

 

you know that person?

 

No. I don't know that person but this is a common thing on this site. Haven't you noticed that most people don't say thank you or at least acknowledge the tutor?