Trigonometric Form of a Complex Number...2

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Feb 19, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.6

    Screenshot_20220218-170321_Samsung Notes.jpg

    IMG_20220219_164127.jpg

    IMG_20220219_164136.jpg

    IMG_20220219_164146.jpg
     
    nycmathguy, Feb 19, 2022
    #1
  2. nycmathguy

    MathLover1

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    4+4sqrt(3)*i

    Use
    z=a+bi=|z|(cos(θ)+i*sin(θ))
    |z|=8
    θ = arctan(b / a)
    θ = arctan(4sqrt(3) / 4)
    θ = arctan(sqrt(3) )
    θ = π/3

    |z|(cos(θ)+i*sin(θ)) =8(cos(π/3)+i*sin(π/3))
     
    MathLover1, Feb 19, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    You said:

    4 + 4sqrt(3)*i

    Question 8 is 4 - 4sqrt(3)*i.
     
    Last edited: Feb 20, 2022
    nycmathguy, Feb 20, 2022
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  4. nycmathguy

    nycmathguy

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    You said to use θ = arctan(b / a).

    Section 6.6 tells me to use θ = 2pi + arctan(b / a).

    Which is it?
     
    nycmathguy, Feb 20, 2022
    #4
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