Trigonometric Form of a Complex Number...4

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Feb 25, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.6

    Screenshot_20220225-103853_Samsung Notes.jpg

    IMG_20220225_114812.jpg

    IMG_20220225_114822.jpg

    IMG_20220225_114837.jpg

    IMG_20220225_114850.jpg
     
    nycmathguy, Feb 25, 2022
    #1
  2. nycmathguy

    MathLover1

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    10.

    (5/2)(sqrt(3)-i)
    =(5/2)sqrt(3)-(5/2)i

    r=sqrt(((5/2)sqrt(3))^2+(5/2)^2)=5

    tan(θ)=(5/2)/(sqrt(3))(5/2)=1/sqrt(3)

    θ=tan^-1(1/sqrt(3))

    θ=π/6

    5(cos(-π/6)+i*sin(-π/6))

    22.

    3sqrt(2)-7i

    r=sqrt((3sqrt(2))^2+7^2)=sqrt(67)

    tan(θ)=7/(3sqrt(2))
    θ=tan^-1(7/(3sqrt(2)))
    θ=1.02591
    or
    θ=58.78°

    z=sqrt(67)(cos(1.02591)+i*sin(1.02591))
    or
    z=sqrt(67)(cos(58.78°)+i*sin(58.78°))
     
    MathLover1, Feb 25, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    I got both wrong. . .again?
     
    nycmathguy, Feb 25, 2022
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