# Use Pythagorean Theorem To find Each Length

Discussion in 'Other Pre-University Math' started by nycmathguy, Aug 11, 2021.

1. ### nycmathguy

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Set 1.4
David Cohen
Question 27

What is the purpose for the exercise?

a^2 = 1^2 + 1^2

a^2 = 2

sqrt{a^2} = sqrt{2}

a = sqrt{2}

That was easy. The hypotenuse for the first right triangle on the far left is sqrt{2}. So what? nycmathguy, Aug 11, 2021

2. ### MathLover1

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correct, and now find b, c, d, e, f, and g

MathLover1, Aug 11, 2021
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3. ### nycmathguy

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This is an exercise involving the Pythagorean Theorem. I have to calculate a^2 + b^2 = c^2 for each triangle. Is this the only purpose for this problem? Did you see my thread Triangle ABC posted today?.

nycmathguy, Aug 11, 2021
4. ### nycmathguy

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I will go as far as finding c.

Find b.

(sqrt{2})^2 + 1^2 = b^2

2 + 1 = b^2

3 = b^2

sqrt{3} = sqrt{b^2}

sqrt{3} = b

Find c.

(sqrt{3})^2 + 1^2 = c^2

3 + 1 = c^2

4 = c^2

sqrt{4} = sqrt{c^2}

2 = c

I am going to stop here.

nycmathguy, Aug 11, 2021
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5. ### MathLover1

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correct

MathLover1, Aug 11, 2021
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