Water Tank

Discussion in 'Calculus' started by nycmathguy, May 30, 2022.

  1. nycmathguy

    nycmathguy

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    Calculus
    Section 2.6

    We have come to the end of Section 2.6 before moving on to derivatives and rates of change. As you know, I like to end each section by posting a few proofs and/or problems that I just don't know how to solve. I don't understand how to do part (a). See my work for part (b).

    Screenshot_20220530-090451_Samsung Notes.jpg

    IMG_20220530_093227.jpg
     
    nycmathguy, May 30, 2022
    #1
  2. nycmathguy

    MathLover1

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    part a.

    salt after t minutes = 30*25*t
    water after t minutes = 5000+25t
    compute concentration= C(t)= (30*25*t)/(5000+25t)

    C(t)=(30*25*t)/(5000+25t).........simplify
    =(30*25*t)/(25(200+t))
    =(30t)/(200+t)-> proven

    part b. correct
     
    MathLover1, May 30, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Part (a) is not so bad. I just didn't know what to do.
     
    nycmathguy, May 31, 2022
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