Reply to thread

Message

the plane is flying at 550 mi per hour, in one minute it will fly 550/60= 55/6 miles per 1 min

let altitude be y, then we have
[ATTACH=full]1197[/ATTACH]

tan(16 )= y/(x+55/6)
y=tan(16 )*(x+55/6)

tan(57 )= y/x
y=tan(57 )*x

since height is same

tan(16 )*(x+55/6)=tan(57 )*x
x=2.0976 -> distance after 1 min

substitute x in formulas above
y=tan(16 )*(2.0976+55/6)
y=3.23mil

y=tan(57 )*2.0976
y=3.23mil

[QUOTE="MathLover1, post: 1099029, member: 280"] the plane is flying at 550 mi per hour, in one minute it will fly 550/60= [B]55/6 miles per 1 min[/B] let altitude be [B]y[/B], then we have [ATTACH=full]1197[/ATTACH] tan(16 )= y/(x+55/6) y=tan(16 )*(x+55/6) tan(57 )= y/x y=tan(57 )*x since height is same tan(16 )*(x+55/6)=tan(57 )*x [B]x=2.0976[/B] -> distance after 1 min substitute x in formulas above y=tan(16 )*(2.0976+55/6) [B][COLOR=#0000b3]y=3.23mil[/COLOR][/B] y=tan(57 )*2.0976 [B][COLOR=#ff0000]y=3.23mil[/COLOR][/B] [/QUOTE]