Amplitude, Period & Phase Shift of Trigonometric Equations

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jun 12, 2022.

  1. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    IMG_20220612_183244.jpg
     
    nycmathguy, Jun 12, 2022
    #1
  2. nycmathguy

    MathLover1

    Joined:
    Jun 27, 2021
    Messages:
    2,989
    Likes Received:
    2,884
    1.

    y=3cos(2x-pi)

    for f (x )=A*(Bx-C)+D, where

    A=amplitude
    B=period
    C/B=phase shift
    D=vertical shift

    B=2, C=pi, D=0
    periodicity of cos (x ) is 2pi

    so,

    amplitude: 3

    period: periodicity/B=2pi/2=pi

    phase shift: pi/2


    2.

    y=-4sec(4x-3pi/2)

    B=2, C=3pi/2, D=0
    periodicity of sec (x ) is 2pi
    function sec (x ) doesn't have amplitude

    so,

    amplitude: none

    period: periodicity/B=2pi/2=pi

    phase shift: C/B=(3pi/2)/2=3pi/4
     
    MathLover1, Jun 13, 2022
    #2
    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

    Joined:
    Jun 27, 2021
    Messages:
    5,386
    Likes Received:
    422
    Pretty easy. This is a walk down memory lane.
    There are three more threads in this forums for you to play with. I will not post new threads until all questions have been answered or at least hints provided.
     
    nycmathguy, Jun 14, 2022
    #3
Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.