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Normal
f(t) = -16t^2 + 64t + 5f(1) = -16*1^2 + 64*1 + 5=53f(3) = -16*3^2 + 64*3+ 5=53points(1,f(1)) =(1,53)(3,f(3))=(1,53)slope=(53-53)/(1-1)=0
f(t) = -16t^2 + 64t + 5
f(1) = -16*1^2 + 64*1 + 5=53
f(3) = -16*3^2 + 64*3+ 5=53
points
(1,f(1)) =(1,53)
(3,f(3))=(1,53)
slope=(53-53)/(1-1)=0
