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Calculus 1
Section 1.4
For part (a), just do (i).
Also, I don't understand part (b).
Section 1.4
For part (a), just do (i).
Also, I don't understand part (b).
a.
find avarage velocity if
i)
t=2 and lasting 0.5seconds=> t=2.5
y=40*2.5-16(2.5)^2=0 ft/s
ii) t=2 and lasting 0.1seconds=> t=2.1
y=40*2.1-16(2.1)^2=13.44 ft/s
iii)
t=2 and lasting 0.05seconds=> t=2.05
y=40*2.05-16(2.05)^2=14.76 ft/s
iv)
t=2 and lasting 0.01seconds=> t=2.01
y=40*2.01-16(2.01)^2=15.76 ft/s
b.
Height of the function is given by
y=40t-16t^2
Require to find the instantaneous velocity when t=2 seconds
To find the velocity, find (dy/dt) first.
(dy/dt) (40t-16t^2)=40-32t
So, velocity is given by v(t)=40-32t
when t=2,
v(2)=40-32*2=40-64=-24ft/s -> instantaneous velocity