Average Velocity & Instantaneous Velocity...1

Discussion in 'Calculus' started by nycmathguy, Mar 26, 2022.

  1. nycmathguy

    nycmathguy

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    Calculus 1
    Section 1.4

    For part (a), just do (i).
    Also, I don't understand part (b).

    Screenshot_20220326-183209_Samsung Notes.jpg
     
    nycmathguy, Mar 26, 2022
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  2. nycmathguy

    MathLover1

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    a.
    find avarage velocity if

    i)
    t=2 and lasting 0.5seconds=> t=2.5

    y=40*2.5-16(2.5)^2=0 ft/s

    ii) t=2 and lasting 0.1seconds=> t=2.1

    y=40*2.1-16(2.1)^2=13.44 ft/s

    iii)
    t=2 and lasting 0.05seconds=> t=2.05

    y=40*2.05-16(2.05)^2=14.76 ft/s

    iv)
    t=2 and lasting 0.01seconds=> t=2.01

    y=40*2.01-16(2.01)^2=15.76 ft/s



    b.

    Height of the function is given by

    y=40t-16t^2

    Require to find the instantaneous velocity when t=2 seconds

    To find the velocity, find (dy/dt) first.


    (dy/dt) (40t-16t^2)=40-32t

    So, velocity is given by v(t)=40-32t

    when t=2,

    v(2)=40-32*2=40-64=-24ft/s -> instantaneous velocity
     
    MathLover1, Mar 27, 2022
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    nycmathguy likes this.
  3. nycmathguy

    nycmathguy

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    Thank you. More Calculus on Sunday.
     
    nycmathguy, Mar 27, 2022
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