70.
||v||=2->Magnitude of the vector
v in direction i+ 3j
The standard form of the vector is image v=ai+bj, so a=1 and b=3
Direction angle is tan(θ )=a/b=1/3
θ =tan^-1(1/3)
θ = 18.43°
Express the following vector in component form:
v=<x,y>
x=2cos(18.43°)=1.89742
y=2sin(18.43°)=0.63229
v=<1.89742,0.63229>
