Convert to Polar Form...5

[nycmathguy]

 

[MathLover1]

yes, but you can simplify it using .sin^2(θ)=1-cos^2(θ)

 

[nycmathguy]

yes, but you can simplify it using .sin^2(θ)=1-cos^2(θ)

View attachment 2262

View attachment 2263

I got it right. Simplifying the problem is a personal preference.