Cost, Revenue & Profit

Discussion in 'Other Pre-University Math' started by nycmathguy, Oct 6, 2021.

  1. nycmathguy

    nycmathguy

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    Section 2.7
    Question 70

    20211003_124059.jpg

    Question 70 is a two-part problem.

    Let me see.

    Profit = revenue -cost.

    Let P(x) = profit

    P(x) = x(50 - 0.002x) - (12x + 150,000)

    P(x) = 50x - 0.000x^2 - 12x - 150,000

    P(x) = -0.000x^2 + 38x - 150,000

    The symbol for at least is ≥.

    The inequality I came up with is the following:

    -0.000x^2 + 38x - 150,000 ≥ 1, 650, 000

    Is this the correct polynomial inequality?

    To find the price per unit, solve the polynomial inequality for x.

    Yes?
     
    nycmathguy, Oct 6, 2021
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    MathLover1 likes this.
  2. nycmathguy

    MathLover1

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    perfect

    you can also use -0.000x^2 + 38x - 150,000 =1, 650, 000 which will give you the number of units sold to make 1, 650, 000 profit
     
    Last edited: Oct 6, 2021
    MathLover1, Oct 6, 2021
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  3. nycmathguy

    nycmathguy

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    Great. There's nothing more important to me than the set up. If the set up is right, I can then move forward. I will ask if my set up is correct for most of my precalculus threads moving forward. When time allows, I will show my work.
     
    nycmathguy, Oct 6, 2021
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