Cost, Revenue & Profit

[nycmathguy]

Section 2.7
Question 70

Question 70 is a two-part problem.

Let me see.

Profit = revenue -cost.

Let P(x) = profit

P(x) = x(50 - 0.002x) - (12x + 150,000)

P(x) = 50x - 0.000x^2 - 12x - 150,000

P(x) = -0.000x^2 + 38x - 150,000

The symbol for at least is ≥.

The inequality I came up with is the following:

-0.000x^2 + 38x - 150,000 ≥ 1, 650, 000

Is this the correct polynomial inequality?

To find the price per unit, solve the polynomial inequality for x.

Yes?

 

[MathLover1]

perfect

you can also use -0.000x^2 + 38x - 150,000 =1, 650, 000 which will give you the number of units sold to make 1, 650, 000 profit

 

[nycmathguy]

perfect

you can also use -0.000x^2 + 38x - 150,000 =1, 650, 000 which will give you the number of units sold to make 1, 650, 000 profit

Great. There's nothing more important to me than the set up. If the set up is right, I can then move forward. I will ask if my set up is correct for most of my precalculus threads moving forward. When time allows, I will show my work.