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Derive the quadratic formula.
Derive Quadratic Formula
- Thread starter nycmathguy
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quadratic formula below
is actually derived using the steps involved in completing the square. It stems from the fact that any quadratic function or equation of the form
y = ax^2 + bx + c
can be solved for its roots. The “roots” of the quadratic equation are the points at which the graph of a quadratic function (the graph is called the parabola) hits, crosses or touches the x-axis known as the xx-intercepts.
So to find the roots or x-intercepts of y =ax^2+bx+c, we need to let y=0. That means we have
ax^2+bx+c=0
From here, I am going to apply the usual steps involved in completing the square to arrive at the quadratic formula.
Step 1: Let y=0
ax^2+bx+c=0
Step 2: Move the constant c to the right side of the equation by subtracting both sides by c .
ax^2+bx+c-c=0-c
ax^2+bx=-c
Step 3: Divide the entire equation by the coefficient of the squared term which is a.
ax^2/a+bx/a=-c/a
x^2+(b/a)x=-c/a
Step 4: Now identify the coefficient of the linear term x
the coefficient of the linear term x is b/a
Step 5: Divide it by 2 and raise it to the 2nd power. Then simplify it further.
((b/a)/2)^2=b^2/(4a^2)
Step 6: Add the output of step #5 to both sides of the equation.
Step 7: Simplify the right side of the equation. Be careful when you add fractions with different denominators. Make sure that you find the correct Least Common Denominator (LCD) when performing addition.
Step 8: Express the trinomial on the left side of the equation as the square of a binomial.
Step 9: Take the square root of both sides of the equation to eliminate the exponent 2 of the binomial.
Step 10: Simplify. Make sure that you attach the ± on the right side of the equation. The left side no longer contains the power 2.
= ±
Step 11: Keep the variable x on the left side by subtracting both sides by b/(2a)
= ±
Step 12: Simplify and we are done!
x = ±
.
is actually derived using the steps involved in completing the square. It stems from the fact that any quadratic function or equation of the form
y = ax^2 + bx + c
can be solved for its roots. The “roots” of the quadratic equation are the points at which the graph of a quadratic function (the graph is called the parabola) hits, crosses or touches the x-axis known as the xx-intercepts.
So to find the roots or x-intercepts of y =ax^2+bx+c, we need to let y=0. That means we have
ax^2+bx+c=0
From here, I am going to apply the usual steps involved in completing the square to arrive at the quadratic formula.
Step 1: Let y=0
ax^2+bx+c=0
Step 2: Move the constant c to the right side of the equation by subtracting both sides by c .
ax^2+bx+c-c=0-c
ax^2+bx=-c
Step 3: Divide the entire equation by the coefficient of the squared term which is a.
ax^2/a+bx/a=-c/a
x^2+(b/a)x=-c/a
Step 4: Now identify the coefficient of the linear term x
the coefficient of the linear term x is b/a
Step 5: Divide it by 2 and raise it to the 2nd power. Then simplify it further.
((b/a)/2)^2=b^2/(4a^2)
Step 6: Add the output of step #5 to both sides of the equation.
Step 7: Simplify the right side of the equation. Be careful when you add fractions with different denominators. Make sure that you find the correct Least Common Denominator (LCD) when performing addition.
Step 8: Express the trinomial on the left side of the equation as the square of a binomial.
Step 9: Take the square root of both sides of the equation to eliminate the exponent 2 of the binomial.
Step 10: Simplify. Make sure that you attach the ± on the right side of the equation. The left side no longer contains the power 2.
Step 11: Keep the variable x on the left side by subtracting both sides by b/(2a)
Step 12: Simplify and we are done!
x = ±
.
- Joined
- Jun 27, 2021
- Messages
- 5,386
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- 422
quadratic formula below
is actually derived using the steps involved in completing the square. It stems from the fact that any quadratic function or equation of the form
y = ax^2 + bx + c
can be solved for its roots. The “roots” of the quadratic equation are the points at which the graph of a quadratic function (the graph is called the parabola) hits, crosses or touches the x-axis known as the xx-intercepts.
So to find the roots or x-intercepts of y =ax^2+bx+c, we need to let y=0. That means we have
ax^2+bx+c=0
From here, I am going to apply the usual steps involved in completing the square to arrive at the quadratic formula.
Step 1: Let y=0
ax^2+bx+c=0
Step 2: Move the constant c to the right side of the equation by subtracting both sides by c .
ax^2+bx+c-c=0-c
ax^2+bx=-c
Step 3: Divide the entire equation by the coefficient of the squared term which is a.
ax^2/a+bx/a=-c/a
x^2+(b/a)x=-c/a
Step 4: Now identify the coefficient of the linear term x
the coefficient of the linear term x is b/a
Step 5: Divide it by 2 and raise it to the 2nd power. Then simplify it further.
((b/a)/2)^2=b^2/(4a^2)
Step 6: Add the output of step #5 to both sides of the equation.
Step 7: Simplify the right side of the equation. Be careful when you add fractions with different denominators. Make sure that you find the correct Least Common Denominator (LCD) when performing addition.
Step 8: Express the trinomial on the left side of the equation as the square of a binomial.
Step 9: Take the square root of both sides of the equation to eliminate the exponent 2 of the binomial.
Step 10: Simplify. Make sure that you attach the ± on the right side of the equation. The left side no longer contains the power 2.
= ±
Step 11: Keep the variable x on the left side by subtracting both sides by b/(2a)
= ±
Step 12: Simplify and we are done!
x = ±
.
Fabulous! Great work! Excellent study notes.
