Describing Function Behavior Part 2

See attachment.

Question 38

Bottom portion of graph:

Function increasing on the open interval
(-infinity, -2), decreasing on the open interval
(-2, -infinity).

Upper portion of graph:

Function decreasing on the open interval
(-infinity, 0) and increasing on the open interval
(0, infinity).

Question 40

Function increasing on the open interval
(-infinity, 3); constant on the open interval
(0, 2); increasing on the open interval
(5, infinity).

You say?

 

38.

f(x)=(x^2+x+1)/(x+1)

Increasing:
-infinity <x<-2 and 0<x<infinity
Decreasing:-2<x<-1,and -1<x<0

40.

Function increasing on the open interval
(-infinity, 3); =>correct

constant on the open interval (0, 2); =>correct

increasing on the open interval (5, infinity)=>correct

 

1. You said:

Increasing:
-infinity <x<-2 and 0<x<infinity
Decreasing:-2<x<-1,and -1<x<0

A. Can you express the above the same way I put it?
B. Are you saying I got 38 wrong?

2. Can you check Describing Function Behavior Part 1?

 

38.

f(x)=(x^2+x+1)/(x+1)=> this function increasing on the two open intervals and decreasing on the two open intervals


Bottom portion of graph:

Function increasing on the open interval
(-infinity, -2), decreasing on the open interval (is same as -infinity <x<-2)
and
Function increasing on the open interval (0, infinity), (is same as 0<x<infinity )

Upper portion of graph:
Increasing:

Function decreasing on the open interval
(-2, 0) and increasing on the open interval
(0, infinity).

 

Perfect. What about Part 1?