# Determine Polar Equation...1

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Mar 14, 2022.

1. ### nycmathguy

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Can you work out 36?

nycmathguy, Mar 14, 2022
2. ### MathLover1

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polar equation of the circle

polar coordinates of the center:
a. (2,pi)
b. (2,3pi/4)
c. (0,0)

The equation of a circle with (h, k) center and r radius is given by:

(x-h)^2 + (y-k)^2 = r^2

This is the standard form of the equation.

a.
given center at (2,π)=>h=2, k=π and radius (let it be) R=sqrt(6)

(x-2)^2 + (y-π )^2 = (sqrt(6))^2
(x-2)^2 + (y-π )^2 = 6

To find the polar form of equation of a circle, replace the value of x = r cos θ and y = r sin θ,
Hence, we get:

(r*cos (θ)-2)^2 + (r*sin (θ)-π)^2 = 6

b. (2,3pi/4)
c. (0,0)

MathLover1, Mar 14, 2022
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3. ### nycmathguy

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Easy to understand this reply. I will do the rest when time allows.

nycmathguy, Mar 15, 2022
4. ### nycmathguy

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nycmathguy, Mar 20, 2022
5. ### MathLover1

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correct

MathLover1, Mar 20, 2022
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