Direction Angle of a Vector

Discussion in 'Geometry and Trigonometry' started by nycmathguy, Jan 29, 2022.

  1. nycmathguy

    nycmathguy

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    Section 6.3

    Screenshot_20220123-112305_Samsung Notes.jpg

    IMG_20220129_125249.jpg

    IMG_20220129_125304.jpg

    IMG_20220129_125312.jpg
     
    nycmathguy, Jan 29, 2022
    #1
  2. nycmathguy

    MathLover1

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    62.

    ||v||=sqrt(x^2+y^2)=sqrt((-5)^2+4^2)=sqrt(41) unit

    Now it is clear that the head of the vector lies in the second quadrant, and we can use a little trigonometry to find out the angle.

    tan (θ)=4/5

    θ=90°+tan ^-1(4/5)≈2.46685rad≈141.34°

    64. direction angle is correct
    need magnitude
     
    MathLover1, Jan 29, 2022
    #2
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  3. nycmathguy

    nycmathguy

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    IMG_20220129_200323.jpg

    IMG_20220129_200330.jpg
     
    nycmathguy, Jan 30, 2022
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