Estimate Limits Numerically

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Exercises 1.2
6 & 8

20211006_201954.jpg


Question 6

The purpose of this table is to see what happens as we get closer and closer to 3. I say x cannot be the number in the middle of the table or 3. I will not evaluate this function at the given x-values here. I just want to know if my reasoning is correct.

Note: The graph tells a different story. I think x tends to -3 not 3. You say?

20211006_232311.jpg


Question 8

The purpose of this table is to see what happens as we get closer and closer to 3. I say x cannot be the number in the middle of the table or 3. I will not evaluate this function at the given x-values here. I just want to know if my reasoning is correct.

Note: The graph tells a different story. Does x really tend to 3?

20211006_233426.jpg
 
Last edited:
reasoning is correct

6.
if you calculate this way, as x->3 limit will be undefined
table
x ........... 2.9 ........... 2.99 ........... 2.999 ........... 3 ........... 3.001 ........... 3.01 ........... 3.1
f(x) ........ 0.17 ........ 0.17 ........ 0.167 ........ (undefined) ........ 0.167 ........ 0.167 ........ 0.16

but, if you simplify function you got y=1/(x+3),
table
x ........... 2.9 ... ........ 2.99 ........... 2.999 ........... 3 ........... 3.001 ........... 3.01 ........... 3.1
f(x) ........ 0.17 ........ 0.167........ 0.16669........ (1/6) ........ 0.16666 ........ 0.166 ........ 0.164

then as x->3 limit will be 1/6

MSP26451df321956e8i842e0000578871bh791fbgg4
 
Last edited:
reasoning is correct

6.
if you calculate this way, as x->3 limit will be undefined
table
x ........... 2.9 ........... 2.99 ........... 2.999 ........... 3 ........... 3.001 ........... 3.01 ........... 3.1
f(x) ........ 0.17 ........ 0.17 ........ 0.167 ........ (undefined) ........ 0.167 ........ 0.167 ........ 0.16

but, if you simplify function you got y=1/(x+3),
table
x ........... 2.9 ... ........ 2.99 ........... 2.999 ........... 3 ........... 3.001 ........... 3.01 ........... 3.1
f(x) ........ 0.17 ........ 0.167........ 0.16669........ (1/6) ........ 0.16666 ........ 0.166 ........ 0.164

then as x->3 limit will be 1/6

MSP26451df321956e8i842e0000578871bh791fbgg4

Using the table is very tedious. This exercise is basically to show students how to find the limit as x tends to a certain value without actually getting there.
 
Take a look at your work. I am to use the values of x given in the table to evaluate f(x).

You said that f(x) = -1/4(x + 1). There's a minus in front of the algebraic fraction. How can the limit be

When it has a minus sign at the top it means that you must find the limit when the desired x comes from the left, meaning that you must find which number the limit goes as x becomes more closer to 3 from the left.
 
When it has a minus sign at the top it means that you must find the limit when the desired x comes from the left, meaning that you must find which number the limit goes as x becomes more closer to 3 from the left.

Yes, I figured that out by reading your reply twice.
 


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