Even & Odd Trigonometric Functions

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Section 4.6

1. How can I tell if a trig function is even, odd or neither using its graph?

2. How is this done algebraically?

3. Can you do 61?

20211116_032434.jpg
 
1. How can I tell if a trig function is even, odd or neither using its graph?

if the graph is symmetric with respect to the origin , a function is odd
if the graph is symmetric to the y- axis, a function is an even function


The majority of functions are neither odd nor even, however, sine and tangent are odd functions and cosine is an even function.

All functions, including trig functions, can be described as being even, odd, or neither.
A function is odd if and only if f(-x) = - f(x) and is symmetric with respect to the origin.
A function is even if and only if f(-x) = f(x) and is symmetric to the y axis.
It is helpful to know if a function is odd or even when you are trying to simplify an expression when the variable inside the trigonometric function is negative.

sin( -x ) = - sin (x) ->a function is odd
cos ( -x ) = cos (x)->a function is even
tan ( -x ) = - tan( x)->a function is odd
cot(-x) = -cot(x) ->a function is odd
sec (-x ) = sec (x)->a function is even
csc ( -x ) = - csc (x)->a function is odd

2.
prove that tangent is an odd function
A function is odd if:
f(-x)=-f(x)

tan(-x)=sin(-x)/cos(-x)=-sin(x)/cos(x)=-sin(x)/cos(x)=-tan(x)

more here:


3.

61. f(x)=x+tan(x)
using a graph
upload_2021-11-17_11-28-13.png

The graph is symmetric with respect to the origin therefore it is on odd function.

algebraically:

f(-x) = -x - tan(-x) = -(x - tan(x)) = -f(x)
 
1. How can I tell if a trig function is even, odd or neither using its graph?

if the graph is symmetric with respect to the origin , a function is odd
if the graph is symmetric to the y- axis, a function is an even function


The majority of functions are neither odd nor even, however, sine and tangent are odd functions and cosine is an even function.

All functions, including trig functions, can be described as being even, odd, or neither.
A function is odd if and only if f(-x) = - f(x) and is symmetric with respect to the origin.
A function is even if and only if f(-x) = f(x) and is symmetric to the y axis.
It is helpful to know if a function is odd or even when you are trying to simplify an expression when the variable inside the trigonometric function is negative.

sin( -x ) = - sin (x) ->a function is odd
cos ( -x ) = cos (x)->a function is even
tan ( -x ) = - tan( x)->a function is odd
cot(-x) = -cot(x) ->a function is odd
sec (-x ) = sec (x)->a function is even
csc ( -x ) = - csc (x)->a function is odd

2.
prove that tangent is an odd function
A function is odd if:
f(-x)=-f(x)

tan(-x)=sin(-x)/cos(-x)=-sin(x)/cos(x)=-sin(x)/cos(x)=-tan(x)

more here:


3.

61. f(x)=x+tan(x)
using a graph
View attachment 1064
The graph is symmetric with respect to the origin therefore it is on odd function.

algebraically:

f(-x) = -x - tan(-x) = -(x - tan(x)) = -f(x)

This is one of the best replies I have seen this far. Give me time to do all even number questions here. This will need to wait for the weekend. Tonight is my Friday at the job. Thank God.
 
1. How can I tell if a trig function is even, odd or neither using its graph?

if the graph is symmetric with respect to the origin , a function is odd
if the graph is symmetric to the y- axis, a function is an even function


The majority of functions are neither odd nor even, however, sine and tangent are odd functions and cosine is an even function.

All functions, including trig functions, can be described as being even, odd, or neither.
A function is odd if and only if f(-x) = - f(x) and is symmetric with respect to the origin.
A function is even if and only if f(-x) = f(x) and is symmetric to the y axis.
It is helpful to know if a function is odd or even when you are trying to simplify an expression when the variable inside the trigonometric function is negative.

sin( -x ) = - sin (x) ->a function is odd
cos ( -x ) = cos (x)->a function is even
tan ( -x ) = - tan( x)->a function is odd
cot(-x) = -cot(x) ->a function is odd
sec (-x ) = sec (x)->a function is even
csc ( -x ) = - csc (x)->a function is odd

2.
prove that tangent is an odd function
A function is odd if:
f(-x)=-f(x)

tan(-x)=sin(-x)/cos(-x)=-sin(x)/cos(x)=-sin(x)/cos(x)=-tan(x)

more here:


3.

61. f(x)=x+tan(x)
using a graph
View attachment 1064
The graph is symmetric with respect to the origin therefore it is on odd function.

algebraically:

f(-x) = -x - tan(-x) = -(x - tan(x)) = -f(x)

Question 58

f(x) = tan x

Symmetric with respect to the origin. Odd function.



20211119_190829.jpg


Question 60

20211119_190905.jpg


Symmetric with respect to the origin. Odd function.

Question 62

f(x) = x^2 - sec x

20211119_190959.jpg


Symmetric with respect to the y-axis. Even function.

Question 64

g(x) = x^2 • cot x

20211119_191043.jpg


Symmetric with respect to the origin. Odd function.

You say?
 


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