Section 2.3 Question 58 [ATTACH=full]398[/ATTACH] If zero is at [B]x = 2/3[/B] one factor of the given polynomial is [B](x - 2/3).[/B] [B] (2/3)(48) = 16 -80 + 16 = -64 (2/3)(-64) = (-128/3) 41 - (-128/3) = (-256/9) -6 - (512/27) = -(674/27) [/B] I say the answer is 48x^2 - 64x - (256/9) with remainder -(674/27). You say?