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Section 2.3
Question 56
Can you do 56 as a guide for me to try a few more on my own?
Question 56
Can you do 56 as a guide for me to try a few more on my own?
56.
f(x)=x^3-52x-96
x=-6
=>(x+6) is a factor
a.
use synthetic division: if (x+1)=0=>x=-1
-6| 1 0 -52 -96
| -6 36 96
|___________________
....1 -6 -16 0 =>resulting coefficients: 1,-6,-16,0
the quotient is x^2-6x-16, and the remainder is 0
factor it:
x^2-6x-16
x^2-8x+2x-16
(x^2-8x)+(2x-16)
x(x-8)+2(x-8)
(x + 2) (x - 8)
so,
f(x)=x^3-52x-96
f(x)=(x+6)(x + 2) (x - 8)
real solutions:
x=-6
x=-2
x=8
if given root =x=-1, then factor is (x-root)=> in your case root =-1 then factor is (x-(-1))=>(x+1)