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If a' has the usual meaning, the derivative of a, then since a= 10, a constant, a'= 0, NOT b= 20.Another, though unlikely, interpretation is that f(x)= ax^2+ b= 10x^2+ 20 so that f'(1), not a', is 20= b.
If a' has the usual meaning, the derivative of a, then since a= 10, a constant, a'= 0, NOT b= 20.
Another, though unlikely, interpretation is that f(x)= ax^2+ b= 10x^2+ 20 so that f'(1), not a', is 20= b.
